Question

Simplificati:

a)$\frac{ x^{5}-5x+4 }{ x^{2} -1}$

b)$\frac{ x^{2} +7x-6x}{ x^{2} -1}$

macar una cine poate, ms :) am impresia ca prima e ireductibila

Answer 1

[tex]a) \frac{x^5-x-4x+4}{(x+1)(x-1)} = \\ \frac{x(x^4-1)-4(x-1)}{(x+1)(x-1)}= \\ \frac{x(x-1)(x+1)(x^2+1)-4(x-1)}{(x+1)(x-1)} = \\ \frac{(x-1)(x(x+1)(x^2+1)-4)}{(x+1)(x-1)}= \\ \frac{x(x+1)(x^2+1)-4}{x+1} [/tex]