Question

simplificati fractia: 2^2007-6×2^2002 totul supra 2^2001+2^2003+2^2004

Answer 1

   (2^2007-6x2^2002)/(2^2001+2^2003+2^2004) = 
= 2^2002(2^5-6) / 2^2001(1+2^2+2^3) = 
= 2^2002 x (32-6) / 2^2001 * (1+4+8) = 
= 2^2002 x 26 / 2^2001 * 13 =
= 2 x 2 = 
= 4