Question

Simplificați fracția: x la a 3 -3x la a 2 - x +3supra la 9-xla a 2 , pentru xapartine R\{-3;3}
va rog muult!!!!!

Answer 1

[tex]\frac{x^3-3x^2-x+3}{9-x^2}=\\ \frac{x^2(x-3)-(x-3)}{(3-x)(3+x)}=\\ \frac{(x-3)(x^2-1)}{(3-x)(x+3)}=\\ \frac{(x-3)(x-1)(x+1)}{-(x-3)(x+3)}=\\ =\frac{(1-x)(x+1)}{x+3} \vee x\in R- \{-3,3\} [/tex]