Question

simplificati fractiile, obtinând fractiile ireductibile

Answer 1

$\frac{3}{6}$ = $\frac{1}{2}$ simplificat prin 3.
$\frac{6}{8}$ = $\frac{3}{4}$ simplificat prin 2.
$\frac{8}{10}$ = $\frac{4}{5}$ simplificat prin 2.
$\frac{12}{18}$ = $\frac{2}{3}$ simplificat prin 6.
$\frac{15}{20}$ = $\frac{3}{4}$ simplificat prin 5.
$\frac{20}{25}$ = $\frac{4}{5}$ simplificat prin 5.
$\frac{28}{42}$ = $\frac{4}{6}$ simplificat prin 7.
$\frac{44}{60}$ = $\frac{11}{15}$ simplificat prin 4.
$\frac{46}{69}$ = $\frac{46}{69}$ e ireductibilă.
$\frac{74}{50}$ = $\frac{37}{25}$ simplificat prin 2.
$\frac{56}{100}$ = $\frac{14}{25}$ simplificat prin 4.
$\frac{60}{90}$ = $\frac{2}{3}$ simplificat prin 30.
$\frac{110}{88}$ = $\frac{55}{44}$ simplificat prin 2,apoi prin 11 $\frac{5}{4}$.
$\frac{96}{120}$ = $\frac{12}{15}$ simplificat prin 8,apoi prin 3 $\frac{4}{5}$.
$\frac{140}{160}$ = $\frac{7}{8}$ simplificat prin 20.