Question

Simplificati urmatoarele fractii, obtinand fractii ireductibile : 

3 la puterea a 2-a x 7 la a 3-a

                                                    

3 la puterea a 3-a x 7 la a 2-a

256

       

2 la puterea a 7-a x 5

14 la puterea a 2-a

                                      

7 la puterea a 2-a x 5

5 la puterea a 2-a -4 la a 2-a

                                                  

2 la a 2-a x 3 la a 2-a

Answer 1

(3²·7³)/(3³·7²)=SE SIMPLIFICA CU 7²SI 3²=7/3
SAU 3²·7³:3³·7²=3²⁻³X7³⁻²=3⁻¹X7=1/3X7=7/3

256/(2⁷X5)=2⁸/(2⁷X5)= SE SIMPLIF.CU 2⁷=2/5

14²/(7²X5)=(2²X7²)/(7²X5)= SESIMPLIF.CU 7²=2²/5=4/5

(5²-4²)/(2²X3²)=(25-16)/(2²X3²)=9/(2²X3²)=3²/(2²X3²)=SE SIMPLIF.CU 3²=1/4