Question

Simplificati x²-8x +16 supra x²-4x
b) x²+2x+1 supra x²-1

Answer 1

$a) \dfrac{x^{2}-8x+16 }{ x^{2} -4x} = \dfrac{ (x-4)^{2}}{x(x-4)} = \dfrac{x-4}{x}= \dfrac{x}{x}- \dfrac{4}{x} =1- \dfrac{4}{x}$

$b) \dfrac{ x^{2} +2x+1}{ x^{2} -1} = \dfrac{ (x+1)^{2} }{(x-1)(x+1)} = \dfrac{x+1}{x-1}$