Question

simplificatii fractiile incat sa devina ireductibile: 2×5×7 supra 3×5×11 si 2 la a 3-a supra 2 la a 5-a

Answer 1

$\frac{2*5*7}{3*5*11} = \frac{2*7}{3*11} = \frac{14}{33}$

$\frac{2 ^{3} }{2 ^{5} } = \frac{1}{2 ^{2} } = \frac{1}{4}$