Question

Simplilificati raportul algebric
[tex] \frac{4a^{2 } -4b ^{2} }{2(b+a) ^{2}
} [/tex]
va roggg

Answer 1

4a^2-4b^2=(2a+2b)(2a-2b)=2*(a+b)*2*(a-b)=4(a+b)(a-b)
Raportul devine
$\frac{4(a+b)(a-b)}{2(a+b)^2}$=$\frac{2(a-b)}{(a+b)}$ (pentru ca am simplificat cu 2(a+b) )