Question

Sin la doua de 135 de grade + sin la a doua de 45 de grade = 1

Answer 1

    
[tex]\displaystyle\\ \sin^2 135^o+\sin^2 45^o = \\\\ = \sin^2 (180^o-45^o)+\sin^2 45^o = \\\\ =\sin^2 45^o+\sin^2 45^o = \\\\ = \left(\frac{\sqrt{2} }{2}\right)^2+\left(\frac{\sqrt{2} }{2}\right)^2=\\\\\\ = \frac{2}{4} + \frac{2}{4} = \frac{2+2}{4} = \frac{4}{4} = \boxed{\bf 1}[/tex]