Question

solutiile reale ale ecuatiei x patrat +2x-63=0 sunt.......si........

Answer 1

x²+2x-63=0

Δ=b²-4ac=4+4*63=4+252=256

√Δ=16

x1= (-b+√Δ)/2a= (-2+16)/2= 7

x2=(-b-√Δ)/2a= (-2-16)/2= -9

S-{ -9, 7}

Answer 2

Răspuns:

x²+2x-63=0 ;  Δ=b²-4ac= 4+252=256 ;   x=(-b+√Δ)/2a= (-2+16)/2=7 ;          x=(-2-16)/2=-9

Explicație pas cu pas: