Question

stabileste compozitia procentuala a elemnetelor din 2 subst compuse
Va roggggggg❤❤❤
Dau 100 pct. ​

Answer 1

Răspuns:

1 NaOH

MNaOH=23+16+1=40g/mol

40gNaOH.................23gNa...............16gO................1gH

100gNaOH...................xgNa..............ygO........ .......zgH

x= 100×23/40= calculeaza

y=100×16/40= calculeaza

z= 100×1/40= calculeaza

2. CaCO3

MCaCO3=40+12+3×16=100g/mol

100g MgCO3...................40gCa.............12gC..................48gO

100gMgCO3...................xgCa..................ygC..................zgO

x=100×40/100= calculeaza

y=100×12/100= calculeaza

z=100×48/100= calculeaza

Explicație: