Question

stabiliti daca numerele1,{2], 2[1], 3[6], 6[3] formeaza o proportie

Answer 1

1,(2)=(12-1)/9=11/9
2,(1)=(21-2)/9=19/9
3,(6)=(36-3)/9=33/9=11/3
6,(3)=(63-6)/9=57/9=19/3

(11/9 )/ 11/3 = 11/9 × 3/11=1/3=0,(3)
(19/9) / 19/3 = 19/9 × 3/19=1/3=0,(3)

deci 1,(2)/3,(6)= 2,(1)/6,(3) = 1/3 =0,(3)