Question

Stabiliți mulțimea soluțiilor pentru fiecare ecuație în parte: a) 4x+7=31 b) -2x+5=11 c) 5x+6=-14 d) 3x+8=14 e) 2x-3=x+2 f) 3x+2=x-6 g) 4x+3=x-15 h) 3x-8=x+4 i) 3x-11=x-23 j) 4x+5=2x+13 k) 5x-9=3x+1 l) 4x-3=-x+17

Answer 1

$a)4x + 7 = 31$

$4x = 31 - 7$

$4x = 24 \: | \div 4$

$x = 6$

$S=\left\{6\right\}$

$b) - 2x + 5 = 11$

$- 2x = 11 - 5$

$- 2x = 6 \: | \div ( - 2)$

$x = - 3$

$S=\left\{ - 3\right\}$

$c)5x + 6 = - 14$

$5x = - 14 - 6$

$5x = - 20 \: | \div 5$

$x = - 4$

$S=\left\{ - 4\right\}$

$d)3x + 8 = 14$

$3x = 14 - 8$

$3x = 6 \: | \div 3$

$x = 2$

$S=\left\{2\right\}$

$e)2x - 3 = x + 2$

$2x - x = 2 + 3$

$x = 5$

$S=\left\{5\right\}$

$f)3x + 2 = x - 6$

$3x - x = - 6 - 2$

$2x = - 8 \: | \div 2$

$x = - 4$

$S=\left\{ - 4\right\}$

$g)4x + 3 = x - 15$

$4x - x = - 15 - 3$

$3x = - 18 \: | \div 3$

$x = - 6$

$S=\left\{ - 6\right\}$

$h)3x - 8 = x + 4$

$3x - x = 4 + 8$

$2x = 12 \: | \div 2$

$x = 6$

$S=\left\{6\right\}$

$i)3x - 11 = x - 23$

$3x - x = - 23 + 11$

$2x = - 12 \: | \div 2$

$x = - 6$

$S=\left\{ - 6\right\}$

$j)4x + 5 = 2x + 13$

$4x - 2x = 13 - 5$

$2x = 8 \: | \div 2$

$x = 4$

$S=\left\{4\right\}$

$k)5x - 9 = 3x + 1$

$5x - 3x = 1 + 9$

$2x = 10 \: | \div 2$

$x = 5$

$S=\left\{5\right\}$

$l)4x - 3 = - x + 17$

$4x + x = 17 + 3$

$5x = 20 \: | \div 5$

$x = 4$

$S=\left\{4\right\}$