Question

Stie careva sa o rezolve ?


$\lim_{x \to 0} \frac{sin(x+3)}{x+2}$

Answer 1

$\lim\limits_{x\to 0}\dfrac{\sin(x+3)}{x+2} = \dfrac{\sin(0+3)}{0+2} = \dfrac{\sin 3}{2}$