Question

Stie cineva rezolvarea? Am trecut log in baza 4 din 9 in baza 3 dar nu stiu daca e bine

Answer 1

Aplici   mai   intai   formula
log(a^k)b^k=log (a)b
log(4)9=log(2²)3²=log(2)3
a=log(3)2³*log(2)3=3log(3)2*log(2)3=3log(3)2*1/log(3)2=3*1=3

Answer 2

$a= log_{3}2^3* log_{2^2}3^2=3 log_{3}2* \frac{2}{2}* log_{2}3=3*1=3$