Question

stiind ca 3a=5b, determinati a/b si 6a+b/ 9a+3b

Answer 1

[tex] \frac{a}{b} = \frac{5}{3} => \frac{a}{5} = \frac{b}{3} = k => a=5*k ; b=3*k [/tex]

$\frac{6*a+b}{9*a+3*b} = \frac{6*5k+3*k}{9*5k+3*3k} = \frac{33k}{54k} = \frac{11}{18}$