Question

stiind ca a=34,3b+c=38 si 10a+6b+2c=xyx in baza 10, ordonati crescator cifrelex,y,z.

Answer 1

a=34
10a=340
6b+2c=38x2=76
340+76=416
10a+6b+2x=xyz=416
4x100+1x10+2=416
416=xyz
y=1
x=4
z=6

Answer 2

a=34
3b+c=38
10a+6b+2c=10*34+2(3b+c)=340+2*38=340+76=416
xyz=416
416=400+10+6=4*10^2+10^1+6*10^0
416 ordonati cres. cifrele =1,4,6