Question

stiind ca . a=cel mai mic nr impar , b= succesorul lui 9, c=a *bimpartit 5 Calculeaza in doua moduri (a+c)*b

Answer 1

a= 1
b = 10
c =( a×b):5 => a×b = 5×c
a×b = 1×10 = 10
c = 10:5 = 2

(a+c)×b = a×b+c×b = 10+2×10 =10 +20 = 30
(a+c)×b =( 1+2)×10 = 3×10 = 30

Answer 2

cel mai mic nr impar=1
a=1

succesorul lui 9=10
b=10

c=a*b:5
=1*10:5
=10:5
=2

1mod (a+c)*b=(1+2)*10
=3*10
=30
2mod (a+c)*b=a*b+c*b=1*10+2*10
=10+20
=30