Question

stiind ca b:a=4 rest 2 ,a+b=97,d=2treimi din b iar c este egal cu incincitul jumatatii lui b,afla sfertul sumei numerelor

Answer 1

b:a=4 =>b=4a
a+b=97
a+4a=97
5a=97
a=97/5
b=4 × 97/5 = 388/5

d= 2/3 × b = 2/3 × 388/5 = 776/15
c=b/2 × 5 = 388/5 × 1/2 × 5 = 388/5 × 5/2 =194

(a+b+c+d)/4 = (97/5 + 388/5 + 194 + 776/15)/4 =
=(485/5 + 194 + 776/15)/4 =
=(97+194+776/15)/4=
=(291 + 776/15)/4=
=(4365/15 + 776/15)/4=
=(5141/15)/4=
=5141/15 × 1/4 =
=5141/60

Baftă!

Answer 2

Sper ca te -am ajutat.