Question

Stiind ca (nr cu bara deasupra)abc+dbc+ebc=1916, afla su.a cifrelor a,b,c,d,e

Answer 1

a-9

b-7

c-2

d-3

e-5

972 + 372 +572 = 1916

Answer 2

abc+dbc+ebc=1916

100a+10b+c+100d+10b+c+100e+10b+c=1916

100(a+d+e)+30b+3c=1916

100(a+d+e)+3(10b+c)=1916

100(a+d+e)+3bc=1916

100(a+d+e)+3bc=1700+ 216; (pentru ca 216 este divizibil cu 3)

100(a+d+e)+3•bc=100•17 + 3•72

=> a+d+e=17 si bc=72, deci, b=7 si c=2

a+d+e+b+c=17+7+2= 26