Question

stiind ca x+4y+2z=13 su 3x+2z=11, determinati x+y+z

Answer 1

x+4y+2z=13 (1)
3x+2z=11 (2)
(1)+(2)=4x+4y+4z=24
4(x+y+z)=24
x+y+z=24÷4
x+y+z=6

Answer 2

adunam ambele relatii

x + 4y + 2z  + 3x + 2z = 13 + 11

4x + 4y + 4z = 24

4 (x + y + z) = 24

x + y + z = 24 : 4

x + y + z = 6