Question

sub D. 1,2 si 5 chimie

Answer 1

1) H3C-CH(CH3)-C≡CH
2) C5H8 + H2O = C5H10O (3-metil-2-butanona)
M C5H10O = 5*12+10+16 = 86
1 mol alchină.....86 g C5H10O
4 moli alchină.............x
x = 344 g C5H10O
5) n CH2=CH-O-CO-CH3 => (-CH2-CH-)n
                                                          O-CO-CH3
randament = m practică/m teoretică *100
m practică = 704*80/100 = 536,2 t acetat de vinil
M C4H6O2 = 4*12+6+2*16 = 86
n*86 g acetat............86n g polimer
536,2 t acetat...................x
x = 536,2 t poliacetat de vinil