Question

Subiectul II B. Multumesc mult!

Answer 1

                            C2H5OH                  ⇆                      C2H4          +         H2O
initial :                  a moli
au reactionat :        x
la echilibru :       (a -x)                                                     x                                 x
" " "  " " " " n total = (a+x)    P = 1atm  T = 400K
p etanol/(a-x) = p etena/x = p apa/x = 1atm/(a+x)     
x/a = 0,906    x = 0,906a
p etanol/0,094a = p etena/0,906a = pH2O/0,906a = 1/1,906a ⇒
⇒p etanol = 0,049atm   p etena = pH2O = 0,475 atm
Kp = pC2H4 ·pH2O / pC2H5OH   Kp = 0,475²/0,049 = 4,6 atm
Kx = XC2H4·XH2O/XC2H5OH = [x²/(a+x)²] / [(a-x)/(a+x)] = x²/(a²-x²)
Kx = 0,82/ 0,18 = 4,55 ...cred ca la calcule mai exacte Kp = Kx