Question

Suma a 2 numere naturale este 56. Calculati numerele stiind ca raportul lor este 3/4

Answer 1

a + b = 56
a/b = 3/4
a = 3b/4
3b/4 + b = 56
3b + 4b = 224
7b = 224
b = 224 : 7
b = 32
a = 56 - 32
a = 24

Answer 2

modul 1:
a/b=3/4=0,75
a=0,75b
a+b=56
0,75b+b=56
1,75b=56
b=56/1,75
b=32
32+a=56
a=56-32
a=24
modul 2:
a/b=3/4
a/3=3k
b/4=4k
a+b=56
3k+4k=56
7k=56
k=56/7
k=8
a=3x8=24
b=4x8=32