Question

suma a 3 nr consecutivepare este 48 care sunt nr

Answer 1

a |-----|
b |-----|+2|
c |-----|+2|+2|         } 48.

48 - 6 = 42  ( 3 parti egale)
42 : 3 = 14 (a)
14 +2 = 16 (b)
14 +2+2 = 18 (c)
Proba : 14 +16 +18 = 48.

Answer 2

a+b+c=48
a,b,c=numere.consecutive.pare
a,b,c=?
a=1segment
b=1segment+2
c=1segment+2+2
48-6=42(3segmente.egale)
42:3=14(a)
14+2=16(b)
14+2+2=18(c)
Verificare:14+16+18=48