Question

suma a 3 nr.este 139,daca din fiecare nr.scad acelasi nr.se obtin nr.19 57 6

Answer 1

a+b+c=139
19+57+6=82
139-82=57
57:3=19
a=19+19=38
b=19+57=76
c=19+6=25

Answer 2

x+19+x+57+x+6=139
3x+82=139
3x=57
x=57÷3
x=19
19+19=38 (primul)
19+57=76 (al ll-lea)
19+6=25 (ultimul nr)