Question

Suma a 3 nr nat consecutive impare ese 33 aflati nr

Answer 1

Raspuns:
a numar impar, b=a+2, c=a+4 alte 2 numere impare consecutive
a+(a+2)+(a+4)=33⇒3a+6=33⇒3a=33-6⇒3a=27
a=27:3
a=9
a=9, b=a+2=9+2=11, c=a+4=13
 numerele sunt  {9,11,13}

verificare
a+b+c=33⇒9+11+13=33⇒33=33