Question

Suma a 3 numere este 1. Stiind ca ele sunt direct proportionale cu 0,1; 2/5 ; 1/3 , aflati numerele?

Answer 1

x=0,1k
y=2k/5
z=k/3
x+y+z=1
0,1k+2k/5+k/3=1
k/10+2k/5+k/3=1
3k+12k+10k=30
25k=30
k=30/25=6/5
x=0,1k=1/10 × 6/5=6/50=3/25
y=2k/5=2/5 × 6/5=12/25
z=k/3=6/5 :3=6/15=2/5
veriicare
3/25+12/25+2/5=(3+12+10)/25=1

Answer 2

a+b+c=1
0,1=1/10
{a,b,c}dp{1/10,2/5,1/3}
10a=5b/2=3c=k
a=k/10
b=2k/5
c=k/3
k/10+2k/5+k/3=1
(3k+2x6k+10k)/30=1
25k=30
k=30/25=6/5

a=k/10=6/5x1/10=3/25
a=3/25=0,12
b=2k/5=(2x6/5)/5=12/25
b=12/25=0,48
c=k/3=6/5)/3=2/5=0,4

0,12+0,48+0,4=1