Question

Suma a 4nr naturale consecutive este 50 . aflati nr.

Answer 1

n+n+1+n+2+n+3=50
4xn+6=50
4xn=50-6
4xn=44
n=44:4
n=11
n+1=11+1=12
n+2=11+2=13
n+3=11+3=14
proba: 11+12+13+14=50

Answer 2

Primul nr.=a
Al doilea=a+1
Al treilea=a+2
Al patrulea=a+3
a+(a+1)+(a+2)+(a+3)=50
Deci:
50-6=44
44:4=11
Răspuns:
Primul:11
Al doilea:11+1=12
Al treilea:11+2=13
Al patrulea:11+3=14