Question

suma a 8 nr. naturale consecutive impare este egala cu 192.determinati  cele 8 nr. naturale

Answer 1

n+1+n+3+n+5+n+7+n+9+n+11+n+13+n+15=192
8n+64=192
8n=128  |:8
n=16
n+1=17
n+3=19
n+5=21
n+7=23
n+9=25
n+11=27
n+13=29
n+15=31

Answer 2

          
$x=\text{cel mai mic numar} \\ x + (x+2)+ (x+4)+ (x+6)+ (x+8)+ \\ + (x+10)+ (x+12)+ (x+14)=192 \\ 8x+2 +4+6+8+10+12+14=192 \\ 8x+ \frac{7(14+2)}{2} = 192 \\ 8x+7*8=192 \\ 8x+56=192 \\ 8x=192-56 \\ 8x=136 \\ x=136:8 = \boxed{17} \\ \text{Numerele sunt: }17; 19; 21; 23; 25; 27; 29; 31.$