Question

Suma a doua numere naturale este 56. Calculati numerele, stiind ca raportul lor este $\frac{3}{4}$

Answer 1

a+b=56

a/b=3/4 => a=3b/4

3b/4+b=56

amplificam cu 4=> 3b+4b=56*4=> 7b=224 => b=32

a=56-32=24

Answer 2

a+b=56
a=56-b
$\frac{a}{b}= \frac{3}{4} => \frac{56-b}{b}= \frac{3}{4}=>3b=224-4b=>7b=224=>b= 32=> \\ a=56-32=>a=24$