Question

Suma a doua numerereale este egala cu 7.Determinati aceste numere,daca triplul primului numar este 5 mai mare decit al doilea numar.

Answer 1

a+b=7
3a=b+5⇒b=3a-5
a+3a-5=7
4a=12
a=3
b=7-3
b=4

Answer 2

$a+b=7 \\ 3a=5+b \ sau \ b+5=3a \to \fbox{b=3a-5} \\ ************************\\ \\ a+3a-5=7\\4a-5=7\\4a=7+5\\4a=12 \\ a=12:4\\ \boxed{\bold{a=3}} \\ \\ b=3*3-5\\ a=9-5\\ \boxed{\bold{a=4}}$

$\text{Verificare:} \\ 3+4=7 \ (\text{A})\\ \\ 3*3=4+5\\9=9 \ (\text{A})$