Question

Suma a patru nr impare consecutive este248. Aflati nr.

Answer 1

$a+a+2+a+4+a+6=248 \\ 4a+12=248 \\ 4a=248-12 \\ a=236:4 \\ a=59 \\ nr.sunt:59,61,63,65$

Answer 2

a-impar
a + a+2 + a+4 +a+6 =248
4a + 12 = 248
4a =248-12
4a =236
236:4=59   rezulta ca a=59
59+59+2+59+4+59+6 = 248
59+61+63+65 =248
sper ca te am ajutat