Question

Suma a patru numere impare consecutive este 75. Afla numerele.

Answer 1

a+a+2+a+4+a+6=75
4a=75-12
4a=63
a=63:4=15.75
b=16.75
c=17.75
d=18.75

Answer 2

$a+a+2+a+4+a+6=75$
$4a+12=75$
$4a=75-12$
$4a=63$
$a=63:4$
$\boxed{a=15,75}$
$\boxed{b=16,75}$
$\boxed{c=17,75}$
$\boxed{d=18,75}$