Question

Suma a patru numere naturale consecutive pare este 900.Care sunt numerele?

Answer 1

a |-----|
b |-----|2|
c |-----|2|2|
d |-----|2|2|2|          } 900.

900 - ( 2×6)= 900 - 12 = 888 ( 4 segmente egale)
888 : 4 = 222 (a)
222 +2 = 224 (b)
222 +2+2 = 226 (c)
222 +2+2+2 = 228 (d)
Verificare: 222 +224 + 226 + 228 = 900.

Answer 2

a+b+c+d=900
a=un seg
b=un seg+2
c=un seg +2+2
d=un seg+2+2+2
2+2+2+2+2+2=12
900-12=888
888:4=222
a=222
b=224
c=222+2+2=226
d=222+2+2+2=228
a+b+c+d=900