Question

Suma a trei Nr e 2002 .Daca din fiecare nr scadem acelasi nr,atunci obtin nr:173,318,723.Care sunt nr initiale?

Answer 1

a+b+c= 2002

a-x=175  a=175+x

b-x=318  b=318+x

c-x=723  c=723+x

175+x+318+x+723+x=2002

3x +1216 =2002

3x=2002-1216

3x = 786

x=262

a=262+175=437

b=262+318=580

c=262+723=985