Question

Suma a trei numere este 9 intregi si 5 supra 12. Al doilea numar este de doua ori mai mare decat primul si cu 3 supra 2 mai mic decat al treilea . Afla cele 3 numere ! Va rog ajutati-ma!

Answer 1

$a,b,c-nr.$

$a + b + c = 9 \frac{5}{12}$

$a + b + c = \frac{9 \times 12 + 5}{12}$

$a + b + c = \frac{108 + 5}{12}$

$a + b + c = \frac{113}{12}$

$b = 2a$

$a = \frac{b}{2}$

$b = c - \frac{3}{2}$

$c = b + \frac{3}{2}$

$\frac{b}{2} + b + b + \frac{3}{2} = \frac{113}{12} \: | \times 12$

$6b + 12b + 12b + 18 = 113$

$6b + 12b + 12b = 113 - 18$

$30b = 95$

$b = \frac{95}{30}$

$b = \frac{19}{6}$

$a = \frac{b}{2}$

$a = \frac{ \frac{19}{6} }{2}$

$a = \frac{19}{6} \times \frac{1}{2}$

$a = \frac{19}{12}$

$c = b + \frac{3}{2}$

$c = \frac{19}{6} + \frac{3}{2}$

$c = \frac{19}{6} + \frac{9}{6}$

$c = \frac{28}{6}$

$c = \frac{14}{3}$