Question

Suma a trei numere naturale consecutive pre este 168.Determinati numerele.

Answer 1

daca sunt numere consecutive, sunt de forma  n, n+1, n+2

n+(n+1) + (n+2) = 168   ==> n+n+1+n+2=168 ==> 3 n +3 = 168 ==> 3n = 165  ==> n=165:3 = 55

n = 55

n+1 = 56

n+2 = 57

Answer 2

$Rezolvare: \\ n+n+1+n+2=168 \\ 3n+1+2=168 \\ 3n+3=168 \\ 3n=168-3 \\ 3n=165 \\ n= \frac{165}{3} \\ n=\boxed{55}(primul) \\ n+1=55+1=\boxed{56} \\ n+2=55+2=\boxed{57}$