Question

suma a trei numere naturale este 2002.Daca din fiecare se scade acelasi numar,atunci se obtine 175,318,723.care sunt numerele initiale DAU COROANA

Answer 1

x+y+z=2002
x-a=175 x=175+a
y-a=318 x=318+a
z-a=723 x=723+a
175+a+318+a+723+a=2002
1216+3a=2002
3a=2002-1216
3a=786
a=786:3
a=262

x-262=175
x=175+262
x=437

y-262=318
y=318+262
y=580

z-262=723
z=723+262
z=985

x+y+z=2002
437+580+985=2002.