Question

suma inverselor numerelor:√4+√3,√3+√2 si √2+√1

Answer 1

1/(√4+√3)+1/(√3+√2)+1/(√2+√1)=
RATIONALIZAM NUMITORUII inmultind prima fractie cu (√4-√3), a 2 cu (√3-√2) si a 3 cu (√2-√1)
(√4-√3)/(√4-√3)(√4+√3)+(√3-√2)/(√3-√2)(√3+√2)+(√2-√1)/(√2-1)(√2+√1)=
(√4-√3)/(4-3)+(√3-√2)/(3-2)+(√2-1)/(2-1)=
√4-√3+√3-√2+√2-1=2-1=1