Question

Sunt 2 probleme ! -prima este in poza -

Un spatiu verde sub forma unui triungji dreptunghic ABC, m<A=90° , impartit in 3 parcele pe care s-au plantat violete , zambile si narcise . Cunoastem : AB=12 m , AC=16m , BM =6m , MN =4 m .
a) Determinati perimetrul terenului plantat cu flori
b) Determinati distanta de la M la AB
c) Ce procent reprezinta suprafata plantata cu zambile din totalul suprafetei plantate cu celelalte tipuri de flori ?

Answer 1

Rezolvarea in imagine!

Answer 2

Salut ,


Problema I
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→→→ AO = 6 cm < = > OC = 6 cm

=> AC = 12 cm


AB = DC = 6√3


m( ‹ D ) = 90°


=> Teorema lui Pitagora
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AC² = AD² + DC² < = > 12² = AD² + ( 6√3 )² < = > 144 = AD² + 108 < = > AD² = 144 — 108 < = > AD² = 36 < = > AD = √36 = 6 cm
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→→→ A = L • l = 6√3 • 6 = 36√3 cm² — Aria ABCD




OC = OB = BC = 6 cm → ‹ OBC = 60° ‹ OBA = 90° — ‹ OBC = 90° — 60° = 30° ‹ MBS = ‹ OBA = 30° — ‹ opuse la vârf => BC = BM = 6 cm → →→→ ‹ BCM = BMC = ( 180° — ‹ CBM ) : 2 = ( 180° — 90° — 30° ) : 2 = 60° : 2 = 30° ‹ OCM = OCB + BCM = = 60° + 30° = 90° → BC² = AB • AS => →→→ 36 = 6√3 • BS => →→→ BS = 36 / 6√3 = 6 / √3= 6√3 / 3 = 2√3 ________________________________________________________ Problema II : Teorema lui Pitagora in triunghiul ABC
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BC² = AB² + AC²
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BC = 20 m
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AM = AC • AB / BC
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AM = 9,6 m
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P = a + b + c =>

P = 12 + 16 + 20 =>

P = 48 m
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A = b • h / 2 < = >

A = 12 • 9,6 / 2 < = >

A = 115,2 / 2 < = >

A = 57,6 cm — Aria ABC
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MC = BC — MB =>

=> MC = 14 cm

=> MN = 4 cm

→→→ NC = 14 — 4

NC = 10 cm

A = 96 m² => 19,2 = x% • 96 m². < = > x% = 19,2 / 96 < = > x% = 0,2 m² →→ x = 20% — suprafața zambile _________________________________________________________