Question

T2:3x5 la puterea 47+ 2x5 la puterea 42+ 6x5la puterea 49

Answer 1

dăm factor comun puterea cea mai mare, apoi efectuăm calculele:

$3 \cdot 5^{47} + 2 \cdot 5^{42} + 6 \cdot 5^{49} = 5^{42} \cdot (3 \cdot 5^{47-42} + 2 + 6 \cdot 5^{49-42}) =$

$= 5^{42} \cdot (3 \cdot 5^{5} + 2 + 6 \cdot 5^{7}) = 5^{42} \cdot (3 \cdot 3125 + 2 + 6 \cdot 78125)$

$= 5^{42} \cdot (9375 + 2 + 468750) = \bf 478127 \cdot 5^{42}$