Question

testul 3 vă rog dau fundă ​

Answer 1

Răspuns:

Explicație pas cu pas:

1. a=√2 ; b=(√3-√2)/(3-2)=√3-√2

a²=2

b²=3+2-2√6=5-2√6≅0,19⇒ a>b

2. a=1+2√2+2+1+2-2√2=6 ⇒a∈N

3.

a)x+1<2 pt x≥-1

x<=1 x∈[-1,1]

b)-x-1<=2 pt x<-1 si x≥-3⇒x∈[-3,-1)

Raspuns:

x∈{-3,-2,-1,0,1}

4. I4x-11I=1

a) x>=11/4 x>=2,75

4x-11=1 4x=12 x=3 solutie convenabila

b) x<11/4

-4x+11=1 4x=10 x=2,5 solutie convenabila

5a)

√135=11,6189 aprox:11,61

b) √8≅2,82

[-2,82]=-3

{-2,8}=0,2 -3+0,2=-2,8

Answer 2

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