Question

${16}^{2x + 1} \div {4}^{2x + 1} + {4}^{2x + 3} \div 4 = 20 \times {4}^{8}$
X=? ​

Answer 1

Răspuns:

Explicație pas cu pas:

$16^{2x+1} : 4^{2x+1} + 4^{2x+3}:4 = 20 * 4^8\\4^{2*(2x+1)} : 4x^{2x+1} + 4^{2x+2} = 20 * 4^8\\4^{4x+2-2x-1} + 4^{2x+2} = 20 * 4^8\\4^{2x+1} + 4^{2x+2} = 20 * 4^8\\4^{2x}*(4 + 16) ) 20 * 4^8\\4^{2x} * 20 = 20 * 4^8\\4^{2x} = 4^8\\2x = 8\\x = 4$

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