Question

$2 \times {2}^{3} \times {2}^{6} \div ( {2}^{2} ) ^{4} + {5}^{0} + {1}^{5 = }$
VĂ ROG AJUȚI-MA!

Answer 1

$2 \times {2}^{3} \times {2}^{6} : ( {2}^{2}) ^{4} + {5}^{0} + {1}^{5} = 2 \times {2}^{3} \times {2}^{6} : {2}^{8} + {5}^{0} + {1}^{5} = 2 \times {2}^{3} \times {2}^{6} : {2}^{8} + 1 + 1 = 2 \times {2}^{3} \times {2}^{6} : \frac{1}{ {2}^{8} } + 1 + 1 = 2 \times 8 \times 64 \times \frac{1}{256} + 1 + 1 = \frac{1024}{256} + 1 + 1 = 4 + 1 + 1 = 6$

Answer 2

2 × 2^3 × 2^6 : (2^2)^4 + 5^0 + 1^5 =

2^10 : 2^8 + 1 + 1 =

2^(10 - 8) + 2 =

2^2 + 2 =

4 + 2 =

6