Question

$3 \sqrt{8} - \sqrt{50} + 2 \sqrt{18}$
$\sqrt{12} - \sqrt{27} -2 \sqrt{75}$
Vă rog ajutați-mă!!!?
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Answer 1

Răspuns:

Explicație pas cu pas:

$\bf 3\sqrt{8} -\sqrt{50} +2\sqrt{18} =$

$\bf 3\sqrt{2^{3}} -\sqrt{2\cdot5^{2}} +2\sqrt{2\cdot3^{2}} =$

$\bf 3\cdot 2\sqrt{2} -5\sqrt{2} +2\cdot3\sqrt{2} =$

$\bf 6\sqrt{2} -5\sqrt{2} +6\sqrt{2} =$

$\bf 12\sqrt{2} -5\sqrt{2} =\green{\underline{~7\sqrt{2}~}}$

__________________

$\bf \sqrt{12} -\sqrt{27} +2\sqrt{75} =$

$\bf \sqrt{2^{2}\cdot3} -\sqrt{3^{3}} +2\sqrt{3\cdot5^{2}} =$

$\bf 2\sqrt{3} -3\sqrt{3} +2\cdot5\sqrt{3} =$

$\bf 2\sqrt{3} -3\sqrt{3} +10\sqrt{3} =$

$\bf 12\sqrt{3} -3\sqrt{3}=\blue{\underline{~9\sqrt{3}~}}$

$==pav38==$  

Answer 2

$\it 3\sqrt8-\sqrt{50}+2\sqrt{18}=\sqrt2(3\sqrt4-\sqrt{25}+2\sqrt9)=\sqrt2(6-5+6)=7\sqrt2\\ \\ \\ \sqrt{12}-\sqrt{27}-2\sqrt{75}=\sqrt3(\sqrt4-\sqrt9-2\sqrt{25})=\sqrt3(2-3-10)=-11\sqrt3$