Question

$(3 \times {2}^{4} + {2}^{25} \div {2}^{21} ) \div {2}^{3} =$

Answer 1

$(3 \times {2}^{4} + {2}^{25} : {2}^{21}) : {2}^{3} = \\ \\ (3 \times {2}^{4} + {2}^{4}) : {2}^{3} = \\ \\ 4 \times {2}^{4} : {2}^{3} = \\ \\ {2}^{2} \times {2}^{4} : {2}^{3} = \\ \\ {2}^{6} : {2}^{3} = \\ \\ {2}^{6 - 3} = \\ \\ {2}^{3} = \\ \\ 8$

Answer 2

(3 x 2⁴ + 2²⁵:2²¹) :2³ = (3 x 2⁴ + 2²⁵⁻²¹):2³ = (3·16+16):8 = 16·(3+1):8 = 2·4 = 8