Question

${4x - 2 (y + 1) = 2 3x - 2y = 1$
rezolva prin metoda reduceri .Va rog ajutați

Answer 1

4x-2(y+1)=1
23x-2y=1
4x-2y=3
23x-2y=1
4x-2y=3
-23x+2y=-1
-19x=2
x=-2/19
4×(-2/19)-2y=3
y=-65/38
4×(-2/19)-2(-65/38+1)=23×(-2/19)-2(-65/38)=1
1=1=1
(x,y)=(-2/19,-65/38)