Question

$5hm \: + \: 420dm \: + \: 0.04 \: = \: m$

$4.7 \: hm {}^{2} + \: 10.4 \: dam {}^{2} \: - \: 97.573 {m}^{2} = \: hm {}^{2}$

$7 {hm}^{3} + 10.0043 {m}^{3} \: - \: 62dam {}^{3} = \: hm {}^{3}$

Answer 1

$\star)5 \: hm + 420 \: dm + 0.04 \: dam$

$5 \: hm = 500 \: m$

$420 \: dm = 42 \: m$

$0.04 \: dam = 0.4 \: m$

$500 \: m + 42 \: m + 0.4 \: m = 542.4 \: m$

$\star)4.7 \: {hm}^{2} + 10.4 \: {dam}^{2} - 97.573 \: {m}^{2}$

$10.4 \: {dam}^{2} = 0.104 \: {hm}^{2}$

$97.573 \: {m}^{2} = 0.0097573 \: {hm}^{2}$

$4.7 \: {hm}^{2} + 0.104 \: {hm}^{2} - 0.0097573 \: {hm}^{2} = 4.7942427 \: {hm}^{2}$

$\star)7 \: {hm}^{3} + 10.0043 \: {m}^{3} - 62 \: {dam}^{3}$

$10.0043 \: {m}^{3} = 0.0000100043 \: {hm}^{3}$

$62 \: {dam}^{3} = 0.062 \: {hm}^{3}$

$7 \: {hm}^{3} + 0.0000100043 \: {hm}^{3} - 0.062 \: {hm}^{3} = 6.9380100043 \: {hm}^{3}$