Question

$Calculati: 1 : acoloada \frac{1}{3}+ \frac{12}{13} * [ \frac{1}{3}+1 : ( \frac{1}{7} + \frac{1}{2} * \frac{2}{7} )]}$ acoloada

Answer 1

1:{ 1/3 +12/13*[1/3+1:(1/7+1/2*2/7)]}=
= 1:{1/3 +12/13*[1/3+1:(1/7+1/7)]}=
= 1:[1/3 +12/13*(1/3+1:2/7)]=
= 1:[1/3 +12/13*(1/3+1*7/2)]=
= 1:[1/3 +12/13*(1/3+7/2)]=
= 1:[1/3 +12/13*(2/6+21/6)]=
= 1:(1/3 +12/13*23/6)=
= 1:(1/3 +46/13)=
= 1:(138/39+13/39)=
= 1:151/39= 
= 1* 39/151 = 39/151

Ori e asa, ori m-am incurcat eu in calcule. (Desi, eu cred, si sper, ca nu)

Answer 2

1:{1/3+12/13x[1/3+1:(1/7+1/2x2/7)]}=
=1:{1/3+12/13x[1/3+1:(1/7+1/7)]}=
=1:[1/3+12/13x(1/3+1:2/7)]=
=1:[1/3+12/13x(1/3+1x7/2)]=
=1:[1/3+12/13x23/6)]=
=1:(1/3+46/13)=
=1:[(13+138)/39]=
=1:151/39=
=39/151